George had 286 more coins than Perry at first. Then George bought 48 more coins. In the end, George has 3 times as many coins as Perry.
- How many coins did Perry have?
- Find the total number of coins George and Perry had in the end?
| |
George |
Perry |
Total |
| Before |
1 u + 286 |
1 u |
|
| Change |
+ 48 |
|
|
| After |
1 u + 286 + 48 |
1 u |
4 u |
(a)
Before
Number of coins that George had = 1 u + 286
Number of coins that Perry had = 1 u
After
Number of coins that George had = 1 u + 286 + 48 = 3 u
Number of coins that Perry had = 1 u
1 u + 286 + 48 = 3u
1 u + 334 = 3 u
3 u - 1 u = 334
2 u = 334
1 u = 334 ÷ 2 = 167
(a)
Number of coins that Perry had
= 1 u
= 167
(b)
Number of coins that George and Perry had in the end
= 3 u + 1 u
= 4 u
= 4 x 167
= 668
Answer(s): (a) 167; (b) 668
