Luis had 251 more beads than Rael at first. Then Luis bought 55 more beads. In the end, Luis has 4 times as many beads as Rael.
- How many beads did Rael have?
- Find the total number of beads Luis and Rael had in the end?
| |
Luis |
Rael |
Total |
| Before |
1 u + 251 |
1 u |
|
| Change |
+ 55 |
|
|
| After |
1 u + 251 + 55 |
1 u |
5 u |
(a)
Before
Number of beads that Luis had = 1 u + 251
Number of beads that Rael had = 1 u
After
Number of beads that Luis had = 1 u + 251 + 55 = 4 u
Number of beads that Rael had = 1 u
1 u + 251 + 55 = 4u
1 u + 306 = 4 u
4 u - 1 u = 306
3 u = 306
1 u = 306 ÷ 3 = 102
(a)
Number of beads that Rael had
= 1 u
= 102
(b)
Number of beads that Luis and Rael had in the end
= 4 u + 1 u
= 5 u
= 5 x 102
= 510
Answer(s): (a) 102; (b) 510
