John had 281 more coins than Warren at first. Then John bought 43 more coins. In the end, John has 3 times as many coins as Warren.
- How many coins did Warren have?
- Find the total number of coins John and Warren had in the end?
| |
John |
Warren |
Total |
| Before |
1 u + 281 |
1 u |
|
| Change |
+ 43 |
|
|
| After |
1 u + 281 + 43 |
1 u |
4 u |
(a)
Before
Number of coins that John had = 1 u + 281
Number of coins that Warren had = 1 u
After
Number of coins that John had = 1 u + 281 + 43 = 3 u
Number of coins that Warren had = 1 u
1 u + 281 + 43 = 3u
1 u + 324 = 3 u
3 u - 1 u = 324
2 u = 324
1 u = 324 ÷ 2 = 162
(a)
Number of coins that Warren had
= 1 u
= 162
(b)
Number of coins that John and Warren had in the end
= 3 u + 1 u
= 4 u
= 4 x 162
= 648
Answer(s): (a) 162; (b) 648
