Warren had 248 more coins than Neave at first. Then Warren bought 52 more coins. In the end, Warren has 4 times as many coins as Neave.
- How many coins did Neave have?
- Find the total number of coins Warren and Neave had in the end?
| |
Warren |
Neave |
Total |
| Before |
1 u + 248 |
1 u |
|
| Change |
+ 52 |
|
|
| After |
1 u + 248 + 52 |
1 u |
5 u |
(a)
Before
Number of coins that Warren had = 1 u + 248
Number of coins that Neave had = 1 u
After
Number of coins that Warren had = 1 u + 248 + 52 = 4 u
Number of coins that Neave had = 1 u
1 u + 248 + 52 = 4u
1 u + 300 = 4 u
4 u - 1 u = 300
3 u = 300
1 u = 300 ÷ 3 = 100
(a)
Number of coins that Neave had
= 1 u
= 100
(b)
Number of coins that Warren and Neave had in the end
= 4 u + 1 u
= 5 u
= 5 x 100
= 500
Answer(s): (a) 100; (b) 500
