Tommy had 206 more coins than Sean at first. Then Tommy bought 46 more coins. In the end, Tommy has 5 times as many coins as Sean.
- How many coins did Sean have?
- Find the total number of coins Tommy and Sean had in the end?
| |
Tommy |
Sean |
Total |
| Before |
1 u + 206 |
1 u |
|
| Change |
+ 46 |
|
|
| After |
1 u + 206 + 46 |
1 u |
6 u |
(a)
Before
Number of coins that Tommy had = 1 u + 206
Number of coins that Sean had = 1 u
After
Number of coins that Tommy had = 1 u + 206 + 46 = 5 u
Number of coins that Sean had = 1 u
1 u + 206 + 46 = 5u
1 u + 252 = 5 u
5 u - 1 u = 252
4 u = 252
1 u = 252 ÷ 4 = 63
(a)
Number of coins that Sean had
= 1 u
= 63
(b)
Number of coins that Tommy and Sean had in the end
= 5 u + 1 u
= 6 u
= 6 x 63
= 378
Answer(s): (a) 63; (b) 378
