Sean had 230 more coins than Dylan at first. Then Sean bought 43 more coins. In the end, Sean has 4 times as many coins as Dylan.
- How many coins did Dylan have?
- Find the total number of coins Sean and Dylan had in the end?
| |
Sean |
Dylan |
Total |
| Before |
1 u + 230 |
1 u |
|
| Change |
+ 43 |
|
|
| After |
1 u + 230 + 43 |
1 u |
5 u |
(a)
Before
Number of coins that Sean had = 1 u + 230
Number of coins that Dylan had = 1 u
After
Number of coins that Sean had = 1 u + 230 + 43 = 4 u
Number of coins that Dylan had = 1 u
1 u + 230 + 43 = 4u
1 u + 273 = 4 u
4 u - 1 u = 273
3 u = 273
1 u = 273 ÷ 3 = 91
(a)
Number of coins that Dylan had
= 1 u
= 91
(b)
Number of coins that Sean and Dylan had in the end
= 4 u + 1 u
= 5 u
= 5 x 91
= 455
Answer(s): (a) 91; (b) 455
