Warren had 275 more marbles than Riordan at first. Then Warren bought 45 more marbles. In the end, Warren has 5 times as many marbles as Riordan.
- How many marbles did Riordan have?
- Find the total number of marbles Warren and Riordan had in the end?
| |
Warren |
Riordan |
Total |
| Before |
1 u + 275 |
1 u |
|
| Change |
+ 45 |
|
|
| After |
1 u + 275 + 45 |
1 u |
6 u |
(a)
Before
Number of marbles that Warren had = 1 u + 275
Number of marbles that Riordan had = 1 u
After
Number of marbles that Warren had = 1 u + 275 + 45 = 5 u
Number of marbles that Riordan had = 1 u
1 u + 275 + 45 = 5u
1 u + 320 = 5 u
5 u - 1 u = 320
4 u = 320
1 u = 320 ÷ 4 = 80
(a)
Number of marbles that Riordan had
= 1 u
= 80
(b)
Number of marbles that Warren and Riordan had in the end
= 5 u + 1 u
= 6 u
= 6 x 80
= 480
Answer(s): (a) 80; (b) 480
