Daniel had 347 more pens than Howard at first. Then Daniel bought 43 more pens. In the end, Daniel has 4 times as many pens as Howard.
- How many pens did Howard have?
- Find the total number of pens Daniel and Howard had in the end?
| |
Daniel |
Howard |
Total |
| Before |
1 u + 347 |
1 u |
|
| Change |
+ 43 |
|
|
| After |
1 u + 347 + 43 |
1 u |
5 u |
(a)
Before
Number of pens that Daniel had = 1 u + 347
Number of pens that Howard had = 1 u
After
Number of pens that Daniel had = 1 u + 347 + 43 = 4 u
Number of pens that Howard had = 1 u
1 u + 347 + 43 = 4u
1 u + 390 = 4 u
4 u - 1 u = 390
3 u = 390
1 u = 390 ÷ 3 = 130
(a)
Number of pens that Howard had
= 1 u
= 130
(b)
Number of pens that Daniel and Howard had in the end
= 4 u + 1 u
= 5 u
= 5 x 130
= 650
Answer(s): (a) 130; (b) 650
