Xavier had 276 more pens than Ken at first. Then Xavier bought 52 more pens. In the end, Xavier has 3 times as many pens as Ken.
- How many pens did Ken have?
- Find the total number of pens Xavier and Ken had in the end?
| |
Xavier |
Ken |
Total |
| Before |
1 u + 276 |
1 u |
|
| Change |
+ 52 |
|
|
| After |
1 u + 276 + 52 |
1 u |
4 u |
(a)
Before
Number of pens that Xavier had = 1 u + 276
Number of pens that Ken had = 1 u
After
Number of pens that Xavier had = 1 u + 276 + 52 = 3 u
Number of pens that Ken had = 1 u
1 u + 276 + 52 = 3u
1 u + 328 = 3 u
3 u - 1 u = 328
2 u = 328
1 u = 328 ÷ 2 = 164
(a)
Number of pens that Ken had
= 1 u
= 164
(b)
Number of pens that Xavier and Ken had in the end
= 3 u + 1 u
= 4 u
= 4 x 164
= 656
Answer(s): (a) 164; (b) 656
