Julie had a collection of 1960 silver, purple and black balls. After Julie gave away 260 silver balls, the number of silver balls was 190 fewer than the number of purple balls. Given that the number of black balls was five times as many as the number of purple balls, how many silver balls did Julie have at first?
| |
Silver balls |
Purple balls |
Black balls |
Total |
| Before |
1 u + 260 |
1 u + 190 |
5 u + 950 |
1960 |
| Change |
- 260 |
|
|
|
| After |
1 u |
1 u + 190 |
5 u + 950 |
|
Number of black balls in the end
= 5 x (1 u + 190)
= 5 u + 950
Total number of balls at first
= 1 u + 260 + 1 u + 190 + 5 u + 950
= 7 u + 1400
7 u + 1400 = 1960
7 u = 1960 - 1400
7 u = 560
1 u = 560 ÷ 7 = 80
Number of silver balls that Julie had at first
= 1 u + 260
= 80 + 260
= 340
Answer(s): 340
