Hilda had a collection of 2020 silver, green and blue balls. After Hilda gave away 260 silver balls, the number of silver balls was 160 fewer than the number of green balls. Given that the number of blue balls was thrice as many as the number of green balls, how many silver balls did Hilda have at first?
| |
Silver balls |
Green balls |
Blue balls |
Total |
| Before |
1 u + 260 |
1 u + 160 |
3 u + 480 |
2020 |
| Change |
- 260 |
|
|
|
| After |
1 u |
1 u + 160 |
3 u + 480 |
|
Number of blue balls in the end
= 3 x (1 u + 160)
= 3 u + 480
Total number of balls at first
= 1 u + 260 + 1 u + 160 + 3 u + 480
= 5 u + 900
5 u + 900 = 2020
5 u = 2020 - 900
5 u = 1120
1 u = 1120 ÷ 5 = 224
Number of silver balls that Hilda had at first
= 1 u + 260
= 224 + 260
= 484
Answer(s): 484
