Julie had a collection of 1770 blue, gold and silver balls. After Julie gave away 200 blue balls, the number of blue balls was 160 fewer than the number of gold balls. Given that the number of silver balls was thrice as many as the number of gold balls, how many blue balls did Julie have at first?
|
Blue balls |
Gold balls |
Silver balls |
Total |
Before |
1 u + 200 |
1 u + 160 |
3 u + 480 |
1770 |
Change |
- 200 |
|
|
|
After |
1 u |
1 u + 160 |
3 u + 480 |
|
Number of silver balls in the end
= 3 x (1 u + 160)
= 3 u + 480
Total number of balls at first
= 1 u + 200 + 1 u + 160 + 3 u + 480
= 5 u + 840
5 u + 840 = 1770
5 u = 1770 - 840
5 u = 930
1 u = 930 ÷ 5 = 186
Number of blue balls that Julie had at first
= 1 u + 200
= 186 + 200
= 386
Answer(s): 386