Ivory had a collection of 2450 green, silver and black balls. After Ivory gave away 340 green balls, the number of green balls was 130 fewer than the number of silver balls. Given that the number of black balls was thrice as many as the number of silver balls, how many green balls did Ivory have at first?
| |
Green balls |
Silver balls |
Black balls |
Total |
| Before |
1 u + 340 |
1 u + 130 |
3 u + 390 |
2450 |
| Change |
- 340 |
|
|
|
| After |
1 u |
1 u + 130 |
3 u + 390 |
|
Number of black balls in the end
= 3 x (1 u + 130)
= 3 u + 390
Total number of balls at first
= 1 u + 340 + 1 u + 130 + 3 u + 390
= 5 u + 860
5 u + 860 = 2450
5 u = 2450 - 860
5 u = 1590
1 u = 1590 ÷ 5 = 318
Number of green balls that Ivory had at first
= 1 u + 340
= 318 + 340
= 658
Answer(s): 658
