Abi had
47 as many lollipops as Charlie. Charlie had
35 as many lollipops as Japheth. If Japheth had 207 more lollipops than Abi, find the total number of lollipops that was shared among these 3 children at first.
Abi |
Charlie |
Japheth |
4x3 |
7x3 |
|
|
3x7 |
5x7 |
12 u |
21 u |
35 u |
Charlie is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Japheth had more than Abi
= 35 u - 12 u
= 23 u
23 u = 207
1 u = 207 ÷ 23 = 9
Total number of lollipops
= 12 u + 21 u + 35 u
= 68 u
= 68 x 9
= 612
Answer(s): 612