Tina had
45 as many candy canes as Andy. Andy had
35 as many candy canes as Neave. If Neave had 65 more candy canes than Tina, find the total number of candy canes that was shared among these 3 children at first.
Tina |
Andy |
Neave |
4x3 |
5x3 |
|
|
3x5 |
5x5 |
12 u |
15 u |
25 u |
Andy is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Neave had more than Tina
= 25 u - 12 u
= 13 u
13 u = 65
1 u = 65 ÷ 13 = 5
Total number of candy canes
= 12 u + 15 u + 25 u
= 52 u
= 52 x 5
= 260
Answer(s): 260