Marion had
45 as many caramel apples as Pierre. Pierre had
34 as many caramel apples as Luke. If Luke had 64 more caramel apples than Marion, find the total number of caramel apples that was shared among these 3 children at first.
Marion |
Pierre |
Luke |
4x3 |
5x3 |
|
|
3x5 |
4x5 |
12 u |
15 u |
20 u |
Pierre is the repeated identity.
LCM of 5 and 3 = 15
Number of more caramel apples that Luke had more than Marion
= 20 u - 12 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Total number of caramel apples
= 12 u + 15 u + 20 u
= 47 u
= 47 x 8
= 376
Answer(s): 376