Barbara had
45 as many candy canes as Michael. Michael had
38 as many candy canes as Sean. If Sean had 308 more candy canes than Barbara, find the total number of candy canes that was shared among these 3 children at first.
Barbara |
Michael |
Sean |
4x3 |
5x3 |
|
|
3x5 |
8x5 |
12 u |
15 u |
40 u |
Michael is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Sean had more than Barbara
= 40 u - 12 u
= 28 u
28 u = 308
1 u = 308 ÷ 28 = 11
Total number of candy canes
= 12 u + 15 u + 40 u
= 67 u
= 67 x 11
= 737
Answer(s): 737