Yoko had
47 as many sweets as Zeph. Zeph had
45 as many sweets as Bobby. If Bobby had 171 more sweets than Yoko, find the total number of sweets that was shared among these 3 children at first.
Yoko |
Zeph |
Bobby |
4x4 |
7x4 |
|
|
4x7 |
5x7 |
16 u |
28 u |
35 u |
Zeph is the repeated identity.
LCM of 7 and 4 = 28
Number of more sweets that Bobby had more than Yoko
= 35 u - 16 u
= 19 u
19 u = 171
1 u = 171 ÷ 19 = 9
Total number of sweets
= 16 u + 28 u + 35 u
= 79 u
= 79 x 9
= 711
Answer(s): 711