Eva had
78 as many lollipops as Henry. Henry had
34 as many lollipops as Sean. If Sean had 77 more lollipops than Eva, find the total number of lollipops that was shared among these 3 children at first.
| Eva |
Henry |
Sean |
| 7x3 |
8x3 |
|
| |
3x8 |
4x8 |
| 21 u |
24 u |
32 u |
Henry is the repeated identity.
LCM of 8 and 3 = 24
Number of more lollipops that Sean had more than Eva
= 32 u - 21 u
= 11 u
11 u = 77
1 u = 77 ÷ 11 = 7
Total number of lollipops
= 21 u + 24 u + 32 u
= 77 u
= 77 x 7
= 539
Answer(s): 539
