Rachel had
67 as many sweets as Lee. Lee had
34 as many sweets as Zeph. If Zeph had 30 more sweets than Rachel, find the total number of sweets that was shared among these 3 children at first.
Rachel |
Lee |
Zeph |
6x3 |
7x3 |
|
|
3x7 |
4x7 |
18 u |
21 u |
28 u |
Lee is the repeated identity.
LCM of 7 and 3 = 21
Number of more sweets that Zeph had more than Rachel
= 28 u - 18 u
= 10 u
10 u = 30
1 u = 30 ÷ 10 = 3
Total number of sweets
= 18 u + 21 u + 28 u
= 67 u
= 67 x 3
= 201
Answer(s): 201