Jen had
45 as many sweets as Glen. Glen had
45 as many sweets as Nick. If Nick had 27 more sweets than Jen, find the total number of sweets that was shared among these 3 children at first.
Jen |
Glen |
Nick |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Glen is the repeated identity.
LCM of 5 and 4 = 20
Number of more sweets that Nick had more than Jen
= 25 u - 16 u
= 9 u
9 u = 27
1 u = 27 ÷ 9 = 3
Total number of sweets
= 16 u + 20 u + 25 u
= 61 u
= 61 x 3
= 183
Answer(s): 183