Natalie had
45 as many sweets as Ahmad. Ahmad had
47 as many sweets as Oscar. If Oscar had 57 more sweets than Natalie, find the total number of sweets that was shared among these 3 children at first.
Natalie |
Ahmad |
Oscar |
4x4 |
5x4 |
|
|
4x5 |
7x5 |
16 u |
20 u |
35 u |
Ahmad is the repeated identity.
LCM of 5 and 4 = 20
Number of more sweets that Oscar had more than Natalie
= 35 u - 16 u
= 19 u
19 u = 57
1 u = 57 ÷ 19 = 3
Total number of sweets
= 16 u + 20 u + 35 u
= 71 u
= 71 x 3
= 213
Answer(s): 213