Lucy had
47 as many mochi balls as Vaidev. Vaidev had
45 as many mochi balls as Henry. If Henry had 114 more mochi balls than Lucy, find the total number of mochi balls that was shared among these 3 children at first.
Lucy |
Vaidev |
Henry |
4x4 |
7x4 |
|
|
4x7 |
5x7 |
16 u |
28 u |
35 u |
Vaidev is the repeated identity.
LCM of 7 and 4 = 28
Number of more mochi balls that Henry had more than Lucy
= 35 u - 16 u
= 19 u
19 u = 114
1 u = 114 ÷ 19 = 6
Total number of mochi balls
= 16 u + 28 u + 35 u
= 79 u
= 79 x 6
= 474
Answer(s): 474