Ivory had
57 as many mochi balls as Wesley. Wesley had
34 as many mochi balls as Carl. If Carl had 39 more mochi balls than Ivory, find the total number of mochi balls that was shared among these 3 children at first.
| Ivory |
Wesley |
Carl |
| 5x3 |
7x3 |
|
| |
3x7 |
4x7 |
| 15 u |
21 u |
28 u |
Wesley is the repeated identity.
LCM of 7 and 3 = 21
Number of more mochi balls that Carl had more than Ivory
= 28 u - 15 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Total number of mochi balls
= 15 u + 21 u + 28 u
= 64 u
= 64 x 3
= 192
Answer(s): 192
