Pamela had
45 as many chocolate bars as Rael. Rael had
310 as many chocolate bars as Fred. If Fred had 114 more chocolate bars than Pamela, find the total number of chocolate bars that was shared among these 3 children at first.
Pamela |
Rael |
Fred |
4x3 |
5x3 |
|
|
3x5 |
10x5 |
12 u |
15 u |
50 u |
Rael is the repeated identity.
LCM of 5 and 3 = 15
Number of more chocolate bars that Fred had more than Pamela
= 50 u - 12 u
= 38 u
38 u = 114
1 u = 114 ÷ 38 = 3
Total number of chocolate bars
= 12 u + 15 u + 50 u
= 77 u
= 77 x 3
= 231
Answer(s): 231