Sarah had
58 as many candy canes as Ben. Ben had
34 as many candy canes as Tommy. If Tommy had 119 more candy canes than Sarah, find the total number of candy canes that was shared among these 3 children at first.
Sarah |
Ben |
Tommy |
5x3 |
8x3 |
|
|
3x8 |
4x8 |
15 u |
24 u |
32 u |
Ben is the repeated identity.
LCM of 8 and 3 = 24
Number of more candy canes that Tommy had more than Sarah
= 32 u - 15 u
= 17 u
17 u = 119
1 u = 119 ÷ 17 = 7
Total number of candy canes
= 15 u + 24 u + 32 u
= 71 u
= 71 x 7
= 497
Answer(s): 497