Anna had
45 as many chocolate bars as Julian. Julian had
35 as many chocolate bars as Seth. If Seth had 26 more chocolate bars than Anna, find the total number of chocolate bars that was shared among these 3 children at first.
Anna |
Julian |
Seth |
4x3 |
5x3 |
|
|
3x5 |
5x5 |
12 u |
15 u |
25 u |
Julian is the repeated identity.
LCM of 5 and 3 = 15
Number of more chocolate bars that Seth had more than Anna
= 25 u - 12 u
= 13 u
13 u = 26
1 u = 26 ÷ 13 = 2
Total number of chocolate bars
= 12 u + 15 u + 25 u
= 52 u
= 52 x 2
= 104
Answer(s): 104