Fanny had
58 as many candy canes as Dylan. Dylan had
34 as many candy canes as Brandon. If Brandon had 102 more candy canes than Fanny, find the total number of candy canes that was shared among these 3 children at first.
Fanny |
Dylan |
Brandon |
5x3 |
8x3 |
|
|
3x8 |
4x8 |
15 u |
24 u |
32 u |
Dylan is the repeated identity.
LCM of 8 and 3 = 24
Number of more candy canes that Brandon had more than Fanny
= 32 u - 15 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
Total number of candy canes
= 15 u + 24 u + 32 u
= 71 u
= 71 x 6
= 426
Answer(s): 426