Yen had
57 as many lollipops as Cody. Cody had
34 as many lollipops as Harry. If Harry had 91 more lollipops than Yen, find the total number of lollipops that was shared among these 3 children at first.
Yen |
Cody |
Harry |
5x3 |
7x3 |
|
|
3x7 |
4x7 |
15 u |
21 u |
28 u |
Cody is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Harry had more than Yen
= 28 u - 15 u
= 13 u
13 u = 91
1 u = 91 ÷ 13 = 7
Total number of lollipops
= 15 u + 21 u + 28 u
= 64 u
= 64 x 7
= 448
Answer(s): 448