Fiona had
45 as many mochi balls as Ken. Ken had
45 as many mochi balls as David. If David had 54 more mochi balls than Fiona, find the total number of mochi balls that was shared among these 3 children at first.
Fiona |
Ken |
David |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Ken is the repeated identity.
LCM of 5 and 4 = 20
Number of more mochi balls that David had more than Fiona
= 25 u - 16 u
= 9 u
9 u = 54
1 u = 54 ÷ 9 = 6
Total number of mochi balls
= 16 u + 20 u + 25 u
= 61 u
= 61 x 6
= 366
Answer(s): 366