Olivia had
57 as many chocolate bars as Zane. Zane had
34 as many chocolate bars as Owen. If Owen had 143 more chocolate bars than Olivia, find the total number of chocolate bars that was shared among these 3 children at first.
Olivia |
Zane |
Owen |
5x3 |
7x3 |
|
|
3x7 |
4x7 |
15 u |
21 u |
28 u |
Zane is the repeated identity.
LCM of 7 and 3 = 21
Number of more chocolate bars that Owen had more than Olivia
= 28 u - 15 u
= 13 u
13 u = 143
1 u = 143 ÷ 13 = 11
Total number of chocolate bars
= 15 u + 21 u + 28 u
= 64 u
= 64 x 11
= 704
Answer(s): 704