Gem had
57 as many candy canes as Ben. Ben had
35 as many candy canes as Ahmad. If Ahmad had 120 more candy canes than Gem, find the total number of candy canes that was shared among these 3 children at first.
Gem |
Ben |
Ahmad |
5x3 |
7x3 |
|
|
3x7 |
5x7 |
15 u |
21 u |
35 u |
Ben is the repeated identity.
LCM of 7 and 3 = 21
Number of more candy canes that Ahmad had more than Gem
= 35 u - 15 u
= 20 u
20 u = 120
1 u = 120 ÷ 20 = 6
Total number of candy canes
= 15 u + 21 u + 35 u
= 71 u
= 71 x 6
= 426
Answer(s): 426