Jean had
58 as many mini cupcakes as Riordan. Riordan had
34 as many mini cupcakes as Will. If Will had 34 more mini cupcakes than Jean, find the total number of mini cupcakes that was shared among these 3 children at first.
| Jean |
Riordan |
Will |
| 5x3 |
8x3 |
|
| |
3x8 |
4x8 |
| 15 u |
24 u |
32 u |
Riordan is the repeated identity.
LCM of 8 and 3 = 24
Number of more mini cupcakes that Will had more than Jean
= 32 u - 15 u
= 17 u
17 u = 34
1 u = 34 ÷ 17 = 2
Total number of mini cupcakes
= 15 u + 24 u + 32 u
= 71 u
= 71 x 2
= 142
Answer(s): 142
