Emma had
45 as many candy canes as Billy. Billy had
310 as many candy canes as Andy. If Andy had 266 more candy canes than Emma, find the total number of candy canes that was shared among these 3 children at first.
Emma |
Billy |
Andy |
4x3 |
5x3 |
|
|
3x5 |
10x5 |
12 u |
15 u |
50 u |
Billy is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Andy had more than Emma
= 50 u - 12 u
= 38 u
38 u = 266
1 u = 266 ÷ 38 = 7
Total number of candy canes
= 12 u + 15 u + 50 u
= 77 u
= 77 x 7
= 539
Answer(s): 539