Nora had
47 as many lollipops as Neave. Neave had
45 as many lollipops as Seth. If Seth had 209 more lollipops than Nora, find the total number of lollipops that was shared among these 3 children at first.
Nora |
Neave |
Seth |
4x4 |
7x4 |
|
|
4x7 |
5x7 |
16 u |
28 u |
35 u |
Neave is the repeated identity.
LCM of 7 and 4 = 28
Number of more lollipops that Seth had more than Nora
= 35 u - 16 u
= 19 u
19 u = 209
1 u = 209 ÷ 19 = 11
Total number of lollipops
= 16 u + 28 u + 35 u
= 79 u
= 79 x 11
= 869
Answer(s): 869