Diana had
45 as many chocolate bars as Flynn. Flynn had
35 as many chocolate bars as Nick. If Nick had 130 more chocolate bars than Diana, find the total number of chocolate bars that was shared among these 3 children at first.
Diana |
Flynn |
Nick |
4x3 |
5x3 |
|
|
3x5 |
5x5 |
12 u |
15 u |
25 u |
Flynn is the repeated identity.
LCM of 5 and 3 = 15
Number of more chocolate bars that Nick had more than Diana
= 25 u - 12 u
= 13 u
13 u = 130
1 u = 130 ÷ 13 = 10
Total number of chocolate bars
= 12 u + 15 u + 25 u
= 52 u
= 52 x 10
= 520
Answer(s): 520