Rachel had
78 as many candy canes as Neave. Neave had
34 as many candy canes as Paul. If Paul had 33 more candy canes than Rachel, find the total number of candy canes that was shared among these 3 children at first.
Rachel |
Neave |
Paul |
7x3 |
8x3 |
|
|
3x8 |
4x8 |
21 u |
24 u |
32 u |
Neave is the repeated identity.
LCM of 8 and 3 = 24
Number of more candy canes that Paul had more than Rachel
= 32 u - 21 u
= 11 u
11 u = 33
1 u = 33 ÷ 11 = 3
Total number of candy canes
= 21 u + 24 u + 32 u
= 77 u
= 77 x 3
= 231
Answer(s): 231