Lucy had
57 as many lollipops as Seth. Seth had
34 as many lollipops as Liam. If Liam had 52 more lollipops than Lucy, find the total number of lollipops that was shared among these 3 children at first.
| Lucy |
Seth |
Liam |
| 5x3 |
7x3 |
|
| |
3x7 |
4x7 |
| 15 u |
21 u |
28 u |
Seth is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Liam had more than Lucy
= 28 u - 15 u
= 13 u
13 u = 52
1 u = 52 ÷ 13 = 4
Total number of lollipops
= 15 u + 21 u + 28 u
= 64 u
= 64 x 4
= 256
Answer(s): 256
