Pamela had
57 as many sweets as Ahmad. Ahmad had
35 as many sweets as Daniel. If Daniel had 220 more sweets than Pamela, find the total number of sweets that was shared among these 3 children at first.
Pamela |
Ahmad |
Daniel |
5x3 |
7x3 |
|
|
3x7 |
5x7 |
15 u |
21 u |
35 u |
Ahmad is the repeated identity.
LCM of 7 and 3 = 21
Number of more sweets that Daniel had more than Pamela
= 35 u - 15 u
= 20 u
20 u = 220
1 u = 220 ÷ 20 = 11
Total number of sweets
= 15 u + 21 u + 35 u
= 71 u
= 71 x 11
= 781
Answer(s): 781