Tiffany had
67 as many lollipops as Jenson. Jenson had
34 as many lollipops as Flynn. If Flynn had 80 more lollipops than Tiffany, find the total number of lollipops that was shared among these 3 children at first.
| Tiffany |
Jenson |
Flynn |
| 6x3 |
7x3 |
|
| |
3x7 |
4x7 |
| 18 u |
21 u |
28 u |
Jenson is the repeated identity.
LCM of 7 and 3 = 21
Number of more lollipops that Flynn had more than Tiffany
= 28 u - 18 u
= 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
Total number of lollipops
= 18 u + 21 u + 28 u
= 67 u
= 67 x 8
= 536
Answer(s): 536
