Elyse had
45 as many chocolate bars as Valen. Valen had
45 as many chocolate bars as Asher. If Asher had 99 more chocolate bars than Elyse, find the total number of chocolate bars that was shared among these 3 children at first.
Elyse |
Valen |
Asher |
4x4 |
5x4 |
|
|
4x5 |
5x5 |
16 u |
20 u |
25 u |
Valen is the repeated identity.
LCM of 5 and 4 = 20
Number of more chocolate bars that Asher had more than Elyse
= 25 u - 16 u
= 9 u
9 u = 99
1 u = 99 ÷ 9 = 11
Total number of chocolate bars
= 16 u + 20 u + 25 u
= 61 u
= 61 x 11
= 671
Answer(s): 671