Jen had
58 as many lollipops as Elijah. Elijah had
35 as many lollipops as Eric. If Eric had 125 more lollipops than Jen, find the total number of lollipops that was shared among these 3 children at first.
Jen |
Elijah |
Eric |
5x3 |
8x3 |
|
|
3x8 |
5x8 |
15 u |
24 u |
40 u |
Elijah is the repeated identity.
LCM of 8 and 3 = 24
Number of more lollipops that Eric had more than Jen
= 40 u - 15 u
= 25 u
25 u = 125
1 u = 125 ÷ 25 = 5
Total number of lollipops
= 15 u + 24 u + 40 u
= 79 u
= 79 x 5
= 395
Answer(s): 395