Cindy had
47 as many lollipops as Harry. Harry had
45 as many lollipops as Albert. If Albert had 171 more lollipops than Cindy, find the total number of lollipops that was shared among these 3 children at first.
Cindy |
Harry |
Albert |
4x4 |
7x4 |
|
|
4x7 |
5x7 |
16 u |
28 u |
35 u |
Harry is the repeated identity.
LCM of 7 and 4 = 28
Number of more lollipops that Albert had more than Cindy
= 35 u - 16 u
= 19 u
19 u = 171
1 u = 171 ÷ 19 = 9
Total number of lollipops
= 16 u + 28 u + 35 u
= 79 u
= 79 x 9
= 711
Answer(s): 711