Vanessa had
45 as many chocolate bars as Riordan. Riordan had
37 as many chocolate bars as David. If David had 161 more chocolate bars than Vanessa, find the total number of chocolate bars that was shared among these 3 children at first.
Vanessa |
Riordan |
David |
4x3 |
5x3 |
|
|
3x5 |
7x5 |
12 u |
15 u |
35 u |
Riordan is the repeated identity.
LCM of 5 and 3 = 15
Number of more chocolate bars that David had more than Vanessa
= 35 u - 12 u
= 23 u
23 u = 161
1 u = 161 ÷ 23 = 7
Total number of chocolate bars
= 12 u + 15 u + 35 u
= 62 u
= 62 x 7
= 434
Answer(s): 434