Hazel had
45 as many mochi balls as Henry. Henry had
34 as many mochi balls as Daniel. If Daniel had 56 more mochi balls than Hazel, find the total number of mochi balls that was shared among these 3 children at first.
| Hazel |
Henry |
Daniel |
| 4x3 |
5x3 |
|
| |
3x5 |
4x5 |
| 12 u |
15 u |
20 u |
Henry is the repeated identity.
LCM of 5 and 3 = 15
Number of more mochi balls that Daniel had more than Hazel
= 20 u - 12 u
= 8 u
8 u = 56
1 u = 56 ÷ 8 = 7
Total number of mochi balls
= 12 u + 15 u + 20 u
= 47 u
= 47 x 7
= 329
Answer(s): 329
