Jean had
57 as many caramel apples as Oliver. Oliver had
34 as many caramel apples as Wesley. If Wesley had 130 more caramel apples than Jean, find the total number of caramel apples that was shared among these 3 children at first.
| Jean |
Oliver |
Wesley |
| 5x3 |
7x3 |
|
| |
3x7 |
4x7 |
| 15 u |
21 u |
28 u |
Oliver is the repeated identity.
LCM of 7 and 3 = 21
Number of more caramel apples that Wesley had more than Jean
= 28 u - 15 u
= 13 u
13 u = 130
1 u = 130 ÷ 13 = 10
Total number of caramel apples
= 15 u + 21 u + 28 u
= 64 u
= 64 x 10
= 640
Answer(s): 640
