Emma had
67 as many candy canes as Mark. Mark had
35 as many candy canes as Jeremy. If Jeremy had 68 more candy canes than Emma, find the total number of candy canes that was shared among these 3 children at first.
Emma |
Mark |
Jeremy |
6x3 |
7x3 |
|
|
3x7 |
5x7 |
18 u |
21 u |
35 u |
Mark is the repeated identity.
LCM of 7 and 3 = 21
Number of more candy canes that Jeremy had more than Emma
= 35 u - 18 u
= 17 u
17 u = 68
1 u = 68 ÷ 17 = 4
Total number of candy canes
= 18 u + 21 u + 35 u
= 74 u
= 74 x 4
= 296
Answer(s): 296