Xuan had
78 as many mini cupcakes as Pierre. Pierre had
34 as many mini cupcakes as Cody. If Cody had 121 more mini cupcakes than Xuan, find the total number of mini cupcakes that was shared among these 3 children at first.
Xuan |
Pierre |
Cody |
7x3 |
8x3 |
|
|
3x8 |
4x8 |
21 u |
24 u |
32 u |
Pierre is the repeated identity.
LCM of 8 and 3 = 24
Number of more mini cupcakes that Cody had more than Xuan
= 32 u - 21 u
= 11 u
11 u = 121
1 u = 121 ÷ 11 = 11
Total number of mini cupcakes
= 21 u + 24 u + 32 u
= 77 u
= 77 x 11
= 847
Answer(s): 847