Jane had
45 as many candy canes as Xavier. Xavier had
37 as many candy canes as Zeph. If Zeph had 161 more candy canes than Jane, find the total number of candy canes that was shared among these 3 children at first.
Jane |
Xavier |
Zeph |
4x3 |
5x3 |
|
|
3x5 |
7x5 |
12 u |
15 u |
35 u |
Xavier is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Zeph had more than Jane
= 35 u - 12 u
= 23 u
23 u = 161
1 u = 161 ÷ 23 = 7
Total number of candy canes
= 12 u + 15 u + 35 u
= 62 u
= 62 x 7
= 434
Answer(s): 434