Gwen had
45 as many candy canes as Owen. Owen had
35 as many candy canes as Lee. If Lee had 39 more candy canes than Gwen, find the total number of candy canes that was shared among these 3 children at first.
Gwen |
Owen |
Lee |
4x3 |
5x3 |
|
|
3x5 |
5x5 |
12 u |
15 u |
25 u |
Owen is the repeated identity.
LCM of 5 and 3 = 15
Number of more candy canes that Lee had more than Gwen
= 25 u - 12 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Total number of candy canes
= 12 u + 15 u + 25 u
= 52 u
= 52 x 3
= 156
Answer(s): 156